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Nerd Love Solve for “i”


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Nerd Love Solve for “i”

Graph by: Tsukasasoul via Graph Jam Builder

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  1. Anthea says:

    Awwww, that’s so sweet, even if it’s not a graph :P

  2. catalanPPCC says:

    Lovely maths.

  3. wtf says:

    lol

    easy ‘equation’ (if it’s that in English?). But there are an infinite ‘equations’ with “i<3u" as an outcome.

  4. zappafrank says:

    Uh, why does the “greater than” sign randomly change to a “less than” sign at the end?

    FAIL.

  5. Leland says:

    Utterly fantastic. Seriously.

  6. Heather says:

    This GraphJam = Made of Win

  7. Rebecca says:

    Um, total fail. i = sqrt (-1) Always. There is no “solve for i”.

    • Besides that says:

      … you cannot have inequalities with imaginary numbers.

      • sane person says:

        i is a variable in this context. not the imaginary number i.

        • Rebecca says:

          To claim that i is a variable in this context is the same as saying “over here, pi is a variable… it’s not *really* pi, it’s a different pi”. i has a set value.

          • Fred says:

            i is frequently a variable in mathematics. Admittedly it’s usually an index, but it’s still entirely valid. The same goes for e too.

            • Rebecca says:

              Note my comment about context. I have *never* seen it used as a variable unless it’s an index. Granted, all my math classes were taught by people as pedantic as I. I’d rather be pedantic than confused, or require a pre-solving explanation of the use of common mathematical terms as variables in this context blahblahblah. :D

          • maestro says:

            You can claim that pi (alpha, e, i and all the others) is a variable at any time as long as you’re consistent.

          • Daphne du Maurier says:

            pi is used for osmotic pressure. so yea, actually, you would say ‘over here, pi is a variable’.

            and if you’ve ever done any computer programming (doubtful since you’ve never heard of a high school chemistry concept…you clearly don’t have that much schooling) then you’ve used the variable i in for loops.

            • poodle_face says:

              I’ve spent a fair part of the past three weeks writing and reviewing coding standards for a new project at work.

              So while you can use “i” for loops, you should really give it a sensible name (such as “iCommentIndex” or “iAddressLoop”) otherwise you might forget what it is you are looping through :)

              • Meg says:

                In every single coding project I’ve worked on, and in every standard I’ve read, index variables are the exception to the “descriptive names” rule, and not without good reason. I, j, and k are the de-facto standard set of loop indices; adding “loop” or “index” at the end is redundant. This is especially true for anything named “i…Index”, since i stands for index. You should never, ever have a problem “forgetting” what you’re looping through due to your index name, either; any non-trivial code block should be commented. Using long names for your indices can get damn ugly if you’re using them frequently inside a block of code, which makes it harder to read and maintain. Just looking at a very simple example:

                for iWidthLoop in width:
                for jHeightLoop in height:
                exampleValue[iWidthLoop] = max(myArray[iWidthLoop][jHeightLoop], myArray[jHeightLoop][iWidthLoop])

                for i in width:
                for j in height:
                exampleValue[i] = max(myArray[i][j], myArray[j][i])

                There are cases when it makes a lot of sense to name your index variables, but they aren’t the norm, and I can’t imagine your suggestions for “sensible” names would be of very much help.

          • Yellowjumper says:

            Personally I’ve used pi to describe stationary distributions and also profit and inflation in economics. Just because you haven’t seen it doesn’t mean that a lot of people don’t go around using that symbol in a different way.
            There is no reason to think in the context of what was stated that i=sqrt(-1),i is obviously a variable if the first line says to solve for it.

          • Paul says:

            Yeah…. you’re right, it is like that, except “pi” is a silly variable name.

    • Nick R. Bocker says:

      so what you’re saying is that nerd love does not exist?

      …that’s so sad. :(

      • Rebecca says:

        Interesting “logical” leap. a and b are mutually exclusive, yet if !a then !b. :)

        Nerd love exists. Real nerd love doesn’t require destroying understood mathematical concepts to “prove” itself. Real nerds in love completely get that.

        Interestingly enough, when my husband posted the “equation” to me, he pouted that I didn’t treat i as a variable. Hmmmm.

    • asdf says:

      Wait a sec – can’t you manipulate i in equations as if it were a variable? I mean, sure, it would be unusual to solve for i where the only unknown in the equation is u…but it doesn’t seem like there’s anything incorrect about it. Am I missing something?

    • Rebecca says:

      And now I’m done. Gotta get some actual work, done. Thanks for the debate, guys!

    • I lose says:

      Noo…it’s a variable.

      “p” denotes most prime numbers, does that mean p = 2×3 is prime?

      “e” is the Oiler number, but I don’t quite see how it fits in e = 3-1

      “m” stands for mass, yet how come we can have 1-m = 15/7?

      All I see is a total math fail in you.

      • Aaaaargh says:

        Historical fail in you then, usually e isn’t the Oiler number but the Euler one. :)

        • Compulsorry says:

          lol! the Oiler number would be o, don’t you think :P

          Anyway, if -7i > -21u => -49i > 441u (square ‘em, that’s what you best do with i) => u < -1/9. So basically I think this says nerds are one short of a ninepack…

          • GrZ says:

            If in this context i was indeed denoting the root of -1, which it isn’t, the inequality wouldn’t make sense from the start anyway since there is no ordering to the complex numbers, meaning inequalities are meaningless.

        • I lose says:

          Sorry, but to Greek it is Όιλερ and I am Greek.

          English fail for me then, but I dont care.

          • Ben says:

            Yeah, ‘i’ can be a variable. There are plenty of letters that denote other things such as v being velocity or m being mass. I think ‘u’ actually stands for initial velocity but no one is complaining about that one.

            Hell, in physics, ‘i’ means current. So unless the square root of -1 is equal to current then we’ve got a really big problem here. (Actually, I think current might be capital i, but that’s down to my terrible physics skills).

            To put it in an obvious context, triangle RST isn’t made up of resistance, speed and time. Variables can be any letter without actually denoting a preset figure or meaning. We’d need a lot more letters.

            Someone else basically said this, but no one seemed to take it on board so…yeah. (: (Oh, and by the way, I suck at math. So what I just said was probably completely innaccurate.)

    • ummmmm says:

      i could also stand for the unit vector , or it could just be a variable standing for whatever the writer of this equation wanted it to.

    • Estelle says:

      Not in Python it doesn’t. Not in Matlab.

    • Jacob says:

      i is not always equal to the square root of negative one. in electrical engineering i is most often used as the variable for current, with j being the square root of negative one. while such constants as i and pi are universal, their representations are not, and must be taken in context.

    • Jesus Advocate says:

      thank u someone finally got it but it took this far for anyone to stop talking about the inequality itself and how i already has a value the entire inequality fails from the beginning before any math is even done

  8. Gia says:

    aww…i should send this to my boyfriend…

  9. ZZCop says:

    So this is saying that I am less then 3 of you? Well, duh! Unless I’m Manuel Uribe and you’re…uh…Yoko Ono.

  10. I lose says:

    That is not for nerds…actually, anybody with a slight knowledge of maths can pull that off.

    The trick would be to add cosines and tangents to make it a hardcore inequality.

  11. Noreen says:

    I like this, but removing the spaces works for me…i<3u

  12. kek says:

    This graph is awsome; it’s the idea that matters, not the exact calculation, you nerds……..

  13. duh says:

    wow, this is cool…. some people on here took it way out of proportion….get a life

  14. John says:

    This is definetly the best graph on GraphJam.
    WIN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  15. whitey138 says:

    amazing “graph” for once. only problem is its been like 8 years since ive been in a math class but i shouldnt it be -21u/-7u? shouldnt it be -7u in order to divide them properly?

    …once again its been a long time so i dont remember. plus someone probably already mentioned this…

  16. truth says:

    Coming from a Dr. of Math…..this is just lame.

  17. what says:

    Graph Jam FAIL

  18. Andreina says:

    Yeah I saw the change from “more than” to “less than” and I had my doubts.. But it is right.. It’s like you divide the equation by 7, which leaves a negative “i”, so to change it positive you multiply both sides by “-1″ and therefore the “>” changes. It is a double step but helps you to see the problem easier rather than having too much to deal with. Sometimes we even forget those elemental things (I’m studying Civil Engineering).

    Good graph jam, though it could only attempt to impress smart girls lol…

  19. cest says:

    SUPERFLY!!!

  20. CheesyBalone says:

    This is adorable!
    Also a little creepy because I just reviewed this math today in class.

  21. Ralf says:

    aww

    i<3u^2

  22. James says:

    Not that the math involved is terribly difficult, but I guess in this day and age, getting a significant percentage of the population to add, subtract, multiply and divide when inequalities are involved is a feat unto itself.

    Apart from the fact that anyone with a working knowledge of mathematics and will look at “i” as the sqrt(-1) and not as a variable (which is what makes the whole matter “work” in the first place, it is entirely possible to start with the given inequality and end up with the rather useless “3u > i”.

  23. GROROHAPIUDHOAIL says:

    “i” can’t be a variable!
    i=-1
    Any nerd knows that!

    • JT says:

      i = -1?
      i =/= -1
      because
      i^2 = -1
      i = sqrt(-1)
      … but regardless, you can always just capitalize the i and change it to an I.

    • ummmmm says:

      i could also be the unit vector .

      Or it could just stand for, you know, whatever.

    • Aliquot says:

      Rofl. The level of fail in your statement is immeasurable.

      “i” can indeed be a variable, there’s no reason not for it to be.

      Furthermore i is not -1… that would be rather useless. I assume you’re thinking of the imaginary unit i=(-1)^(1/2), which still does not constrain i from ever being a variable.

      Before you make claims in such a rude way, you should check your facts.

  24. jrdnllrd says:

    Shouldn’t the sign be switched on the second line and not on the last?

  25. Stochastic Markov says:

    Nerds do not exist. Nerdisms are a threat to the success of society, and perpetuated by popular culture. Because of nerdisms, people subconsciously associate science, math and engineering with being “socially inept” thus avoiding such unpopular fields. We are running out of scientists in the US and soon China, because of their immense quantity of engineers and scientists will become the world superpower.

    • Jesus Advocate says:

      im sry but based on wat ive seen so far on this debate alone, including me, yes nerds do exist

      • Lexi says:

        absoposilutely. the whole being of “graphjam” is based entirely on nerdism! you think someone who is scared of association with math deeming him socially inept would create a graphs about pop culture and well-known social rules and stuff like that?

  26. math teacher says:

    The second line he is subtracting 9x from each side, not dividing, therefor the sign shouldn’t be switched at that point. It should be switched at the 3rd line, as it was shown here. Original poster did it correctly. I can assure you. Just look it over again.

  27. Wani says:

    i is used as a variable by engineers, to denote current from
    what I recall. This is why engineers use j for sqrt(-1).

  28. Spike Page says:

    At first I read it as “I (am) less than three (of) you”….and then I bought a flippin’ clue and figured it out. <3

    As for the validity of the equation, I will leave the sorting-out to the rest of you mathletes. CHEERS!

  29. smileynyc says:

    OK.. I’m brain dead. Can someone explain why i<3u is romantic?

  30. IglooForAHat says:

    So here’s where I get lost. As I understand it, imaginary numbers such as i, the square root of -1, cannot be used in an inequality…

  31. cakeislie says:

    Isn’t this math wrong? If you divide the left side by nine, you have to do it to the number 7 as well

  32. mathteacher says:

    The math is wrong. The answer would be 3i>u, because multiplying (or dividing) both sides of an inequality by a negative integer would ‘flip’ the inequality sign.

    Nice try anyway.

  33. mathteacher says:

    Sorry for the typo. Should have been 3u > i

  34. Ahmed says:

    You can’t use imaginary numbers in inequalities…

    • Wani says:

      Sure you can! Just means u is probably complex. Something
      many relationships have done well to teach me. *cough*

      If u = i/2 (as an example)
      3u = 3i/2
      3i/2 > i

    • Emma says:

      i is not being used as an imaginary number here. It’s a variable, and you can tell that by them saying ‘solve for i’.

  35. OneHappyAtheist says:

    I’m sorry. I never jumped on the “<3" as "heart" bandwagon.
    I read this as "I is less than three of you."

  36. mathisright says:

    well dude, the math is ALLL correct :P

  37. Joey says:

    So much controversy over something that’s entirely correct.

  38. wicked witch says:

    thats rly cute =]
    <3

  39. thestormie says:

    Sheer and romantic smartiepants.

  40. Fiona (: says:

    okay guys .
    this is called a picture that`s supposed to be sweet and cute .
    why are you guys being so picky about the math ?
    get over it .
    if you`re gonna correct math then maybe this isnt the site for you .

  41. rgriffin says:

    Apparently someone never took programming in college…
    FAIL

  42. nuodai says:

    Am I the only one that’s realised that this is actually wrong? I mean, -7/-7 = 1 and -27/-3 = 3, so there’s no sign change at the end; so you end up with i>3u, which is much less romantic!

    • WOWSTER says:

      you are wrong.

    • poodle_face says:

      Not to jump on the band wagon, but that’s not true.

      At the end, you get “-i > -3u”, which means that i must be a smaller absolute number than 3*U is (because -5 is > -10 for example). So when you remove both negative signs, then the 3u (10 in this case) must be greater than the i (5).

      Algebra is much easier with actual numbers :)

    • Lexi says:

      also, since when is -27/-3=3?

  43. johnny+donnyhadababy says:

    hmmm… a lot of people on this site dont know math
    and those who do dont know how to explain math to retards

  44. bb says:

    since when did love have to make sense?

  45. lolwut? says:

    what I don’t get….

    where did this guy get 9x, 7i, and whatever else he used from?

    to me it seems like he just started with a bunch of random numbers, and simplified it down to i<3u

    this is nothing special. i could say:

    8i+20x = 4(5x+10u)
    8i = 40u
    i = 5u
    i<3u

    wow. i proved i<3u. aren't I intelligent…

    If someone can tell me where he got his numbers from, that had any relevance to anything, I'd be glad to hear it.

    • lolwut? says:

      ah. woops. realized my equation was horribly wrong after i posted it. let me give a better one.

      8i+20x = 4(5x+4u)
      8i = 16u
      i = 2u
      i<3u

      • BAM! says:

        The maker of this had no reason for choosing those specific numbers, but he/she does seem to know algebra. Unlike you. Make sure to check your math again.

        2u is not necessarily smaller than 3u. And 5u is perhaps smaller than 3u. You must start with an inequality, or let u equal a set value before you begin your proof.

      • tralala says:

        well that not quite alright. cause if u3u. ex: u=-2=>i=-4, and that would mean that -4<-6(-4<3(-2)) and that wrong……
        the graphjam if awesome anyway:)

    • Aliquot says:

      Right, the creator did start with an arbitrary inequality. The point was to disguise a message a standard problem of arithmetic manipulation. There were an infinite number of points from which he/she could have begun; his is just as arbitrary as yours, but he/she had to choose one.

  46. Jay Esjay says:

    The graphjam end result is correct, while the process is confusing.
    You can keep it simple and avoid division by -7 this way.
    Original expression: 9x – 7i > 3(3x – 7u)
    Expand the bracket: 9x – 7i > 9x – 21u
    Just delete 9x from each side: -7i > -21u
    Now divide by 7 – no need to flip anything: -i > -3u
    Now flip the inequality: i <3 u
    Surely each step is valid, one at a time.
    What confuses is the choice of divisor -7.
    Try i = 3, and u =2: Then 3 -6. True.

    • Jay Esjay says:

      Sorry, the last line has lost the inequality.
      Should read:
      Try i = 3, and u = 2: Then 3-3u, and using the same variables, -3 > -6. True

      • Jay Esjay says:

        I don’t understand why, but the posted math always seems to lose some characters. Let’s revise it anyway;
        The last line of my last post could have read:
        Try i = 3, and u = 2: Then 3 -6. True.

        Also, discussing i as being sqrt(-1) is a red herring. “i “can always be a variable, unless you define it as the imaginary vector. In computer languages, i and n are often used as integer values, and x, y etc as real (decimal) numbers.

        • Jay Esjay says:

          I don’t know what is happening, but the action of posting has removed and changed several parts of my posts. While it is perhaps excessive to keep on about it, I would really like to make my point. So I put it in words.

          The last line of my earlier post could have read:
          Try i = 3, and u = 2: Then 3 less than 6. True.
          And, using the same variables, -3 is greater than -6. True.
          If this isn’t posted correctly, I shall contact the site technical boffs.

  47. Karl says:

    So..the ex must disappear?

  48. bri-la says:

    hAhahaha. Win. :D

  49. Zane says:

    I did the math on this, and doesn’t it end up
    i > 3u?
    Unless I’m a complete retard, (very possible) it should start
    9x-7i < 3(3x-7u)

  50. Pencilsharpener says:

    I know I saw this a few months ago elsewhere. Congratulations to Tsukasasou for ripping off teh Interwebs.

  51. KimchiC says:

    So adorable!

  52. Tsukasa says:

    Geeze… I didn’t think people would be this up in arms about a little math. XD Thanks to the people who liked it. I was really bored one day and put that together. I made the problem using by going backwards though, so the numbers are basically random. I’m sure someone could have done it much better, and I’m sure it’s elsewhere on the internet. But please do at least enjoy it at face value. =P

  53. point_ says:

    can we not just appreciate the thing for what it is, rather than over-analyze every minute detail and get all hot under the collar?

    this stuff shouldn’t matter so much. we get it. you’re smarter than everyone else. so am i.

  54. bleachgrl says:

    This is totally cute. ^^ This is one of the reasons I prefer nerdy boys over the jocks. They know how to be sweet and dedicated to a girl, as opposed to a jock who doesn’t give a care about anyone but themselves. Maybe I’m being stereotypical by saying that, but I’ve never met a jock that I’ve ever been impressed by, but the nerds know how to treat a girl right. X3

  55. Bekky says:

    you guys do realize that continuously using big words every other word doesn’t make you look smart? it makes you look like you’re tying too hard lmao

  56. Jupi says:

    i c whut u did thar

  57. Tintin says:

    i thought it was I fu*k you because it was a di*k and balls… Am I sick?

  58. jocelyne says:

    i think you would have to divide the numbers by seven not subtract because then you wouldnt have >3u youd have <-24u
    am i right?
    i still love this thought
    really cute
    xD

    • David says:

      I think your incorrect.
      In this situation, you normally would try to get the variable you need alone, thus getting the 9x out of the way. So then you have -7i>-21u
      You don’t need a negative variable, and when you divide or multiply by a negative, you must flip the sign around, thus getting i<3u (i is less than 3u)

      Well, I think. I haven't done this stuff since March.

    • MathFailureCop says:

      YOUR MATH FAILS!!!!!!!!!!!!!!!!!!!!!!!

  59. Nerdandproud says:

    Aaawwww so sweeet!

  60. devan says:

    cool idea, but this is wrong. on a couple of levels. i is a hard variable to use (its not an integer people) because it already has a purpose in math. it states the impossibility of a number. e.g. the square root of -9 would be 3i because you cant square root a (-) number, i states that it is out of the realm of “real” numbers. 2) the greater then sign changes from a > to a < randomly. but the concept is pretty cool.

    • EdBorlang says:

      Refer to posts made earlier. I’ll repeat some of the meat.
      Whether i is often used as a variable or the constant (sqrt(-1)) is determined by context. In this context, we see an inequality. Since are meaningless for sqrt(-1), we can infer that i is a variable.

      The greater than sign does not change randomly to a less than sign.
      Refer to this step: -7i/-7 > -21u/-7. We can rewrite this as two steps:
      -7i/7 > -21u/7 => -i > -3u. Then, we add 3u to both sides and add i to both sides: 3u > i. Finally, we generally put the variable we were focusing on on the left-hand side: i < 3u.

    • Anon says:

      lol, EdBorlang missed the best part.
      “i is a hard variable to use (its not an integer people) because it already has a purpose in math.”
      This sentence is fail on so many levels.
      1) WTF is a “hard variable”?
      2) We weren’t restricting to integers, real numbers are generally assumed in this context.
      3) Doesn’t everything used in mathematics have a purpose in mathematics?

      The second best part:
      “[i] states the impossibility of a number. ”
      This is simply false. The making the square root of -1 a constant allows such equations as x^2+1 = 0 to be solved. Thus, in reality, i boldly states that the square root of -1 exists and all results involving i are therefore in existence.

      • NN says:

        Mmmm… You’re directing this to the wrong person.
        EdBorlang only answered the previous post, which is the one that you’re referring to. That post was made by devan.

  61. Mathspedant says:

    Technically it should be “Simplify in terms of i” rather than “Solve for i” as you cannot evaluate i without more information…

  62. Paul says:

    That’s something I would expect to see on XKCD.

  63. ElecEng says:

    I use i to represent electrical current every day and j for imaginary numbers. But i don’t really care about the mathematical validity of this statement and those that do are missing the point. Great post, the romantic in me loves the idea of using an imaginary number in a statement about love.

  64. Ben says:

    This is odd.. Reading through the comments, It is apparently a high school problem, but I can solve this and I’m in 7th grade. quite easy actually.

  65. 1up says:

    Nice one!!! :) This one is original!!!!1!!2

  66. purple says:

    im putting this on stumbleupon,
    partly cause of the pic and partly cause of the comments

  67. cheesebrrgrr says:

    Nerd Love Poem:
    I melt at your gaze
    You make my knees weak
    From your warm smile
    To each rosy cheek
    Just a glimpse of you
    Will make my heart fly
    Your perfection is infinite
    More infinite than Pi.

    • tralala says:

      really cute, even if pi is an irrational number- infinite
      decimal(has an infinite number of decimals) and can be approximated by 3.14. so i<3u <pi

  68. alyssa says:

    This is funny. I think it’s really cute :) and everyone is getting in an argument over the logics. Why can’t we just appreciate it, eh?

    • NN says:

      I totally agree with you. People should just stop overcomplicating it and enjoy it, cause it’s really cute and romantic :)

  69. marci says:

    This would be great but there is a mistake in the 3rd row.
    7i isn’t 7/7i

  70. Descartes says:

    Bon! Vive le Nerde !

    De-constwuction and the witless cwiticism is pour le, ‘ow you say, ‘shoe salesman?’ Oui ?

  71. John says:

    oh.. at first I thought it meant “I want to thrust my throbbing erection repeatedly up and down between your breasts. However, one lives and learns. Thank you all so much.

  72. WTF Humanity WTF says:

    why the hell are you people arguing about this picture?.. you like it or you dont. move on with your life.

  73. Fail says:

    Math fail, you cant have inequalities with imaginary numbers, nice try though

  74. marvo says:

    (a + b) / a != b
    (a + b) / a = b/a

    • AA says:

      the first equation you gave doesn’t seem to work, nor is it relevant to any of this

    • Aliquot says:

      ROFL!

      You crack me up, seriously.

      Your first statement is correct, but completely unrelated to anything going on.

      Your second statement is blatantly incorrect;
      (a+b)/a=1+(b/a) is what you were going for I think.

      This too is completely unrelated to anything being discussed.

  75. vintagegeekgirl says:

    You are aware that read out loud it says
    I is less than three of u
    Or if you solve for u, u is greater than a third of me. Or in fact that you are only slightly better than a third of myself (in ‘english’)
    It’s actually an insult really

    • Aliquot says:

      “Or in fact that you are only slightly better than a third of myself (in ‘english’)”

      There’s no implication of /slightly/ better at all. It would merely state “You are greater than a third of myself.” manipulated in that way. This isn’t really an insult as it is almost definitely true… While it may not sound overly flattering (as it isn’t, explicitly speaking,) it is certainly not an insult. The implication could, indeed, be that you are maybe only equal to half of myself, or it could perhaps be that you are equal to myself times a billion. It’s all left up to the parameters at hand; you can’t simply assume that it is only “slightly greater.”

  76. haizenberk says:

    whatever it is – cool/sweet/otherwise – we are proud to announce you, ladies and gentlemen, that the maths is correct. and that is final.

  77. leo says:

    lol i found this on a friends status. i solved it and imed the answer before i realized what it said and she sed thank you and then i noticed

  78. Sarah says:

    actually when you divide by a negative the sign switches :p so “>” to “<" is correct.

  79. NN says:

    Stop making such a fuss about the maths (which are, btw, correct, as i in the context is being used as a variable) and enjoy the post, which is the truly important thing. It’s really sweet, and romantic if written for one. I loved it :D

  80. Josh Thompson says:

    Ethan, your retarded, when dividing a fraction by a negative number the signs switch. (assuming its a less than/greater than equation)

  81. tiffanie says:

    you all are making this SIMPLE math inequality harder than it has to be!. im an eighth grader and i understood every step they took in solving it. imagine you’re an eighth grade nerd and you like an eighth grade girl. of course you’re gonna make it say i love you!. so stop trying to make it harder than it has to be people, damn!.

  82. Penis says:

    Penis hair.

  83. FlakAttack says:

    you cant have imaginary numbers in inequalities

  84. ASK5555 says:

    you are all wrong i and u are not like terms so you cant divide them

  85. pablo says:

    wow you people are awful at math who say this is wrong. just stop making fools of yourselves haha idiotsss they may not be like terms but you can still divide the -7 into the 21 genius

  86. Joy says:

    The math is correct! Plus, it’s adorable. SO, stop arguing about it! :)

  87. Joy says:

    adn also I is an imaginary number!!! SO SHUT UP :) ))))

  88. Math Police says:

    JESUS CHRIST! What a bunch of math-illiterate inbred idiots!

    If you can’t figure out how an inequality works please go play in traffic.

  89. nnd says:

    you can’t have inequalities for i

  90. j+r says:

    OMG U GUYS NEED TO SHUT THE F**K UP!!!!! YOU NO NOTHINGGG AND THIS IS FRKN ADORABLE!!!!! AND MY BOYFRIENDS THINKS ITS CUTE TOO!!!!:] (i love him so much:])

  91. Allie says:

    Anyone who says this is wrong is retarded. It’s all right. i is only a variable, no one ever said it had to be imaginary. Pick up a middle school textbook people. This stuff isnt hard. Basic algebra that I learned in 8th grade is what this is.

  92. MEH says:

    It’s fine, but I can understand how people got confused. It isn’t written very clearly. Here’s the process explained.

    Whoever made this should have started backwards, to avoid confusion :P

    3(3x-7u)<9x-7i
    9x-21u<9x-7i
    Subtract 9x from both sides
    -21u<-7i
    divide both sides with 7
    -3u<-i
    add 3u+i to both sides (it's what actually happens)
    i<3u

    Done, it's what was done in the picture in plain math english :D

    It's pretty cute ;)

    • KL says:

      How is “divide both sides with 7″ (which is nonsense – you divide BY 7, not “with” 7) followed by “add 3u+i to both sides” in any way clearer than just dividing both sides by -7? You’re replacing one simple step with two steps for no reason at all.

      • Rod says:

        yes, there was a reason… people got confused by the flip of inequality when dividing both sides by negative #….

        these extra steps let it clearly…. i hope.

  93. yourboss says:

    OK, the last expression is correct you dam retards!!!
    Go relearn your effing algebra otherwise shut the hell up!!
    your daddy at math..

  94. x says:

    ¡Qué pendejada!

  95. gary says:

    you’re all a bunch of freakin idiots. YOU CANT HAVE INEQUALITIES WITH IMAGINARY NUMBERS

  96. matt says:

    Awesome equation, horrible replies, all i saw was arguing about weather the math was correct or not

  97. mickey says:

    d maths is absolutely ri8 n dis is lovingly fantastic !!!!

  98. knightsintodreams says:

    is this mathematically sound? please tell me,
    solving it myself would hardly prove anything -.= *art student
    My big brother just transfered into the Business major at the Udub and his first day is coming up!! i want to leave this on the coffee machine on his first day :3 as encouragement and that me and my elder brother are so so proud of him!!!
    ! (he’s coming in as a Junior, so he doesn’t know anyone) please reply, he’ll laugh at me if it’s wrong haha

  99. Mo says:

    I find it funny that one person explains how it is correct, yet others insist on saying it as well. Losers haha

  100. Momo says:

    Seriously guys?!? First, the math is correct, and second, even if it isn’t, it’s still pretty sweet! Just drop it! I’m getting pretty tired of random people claiming to be “teachers” and “mathematicians” debating their unsubstantiated claims. This is the INTERNET! NOBODY CARES!

  101. A says:

    WOW You guys really are NERDS. It’s supposed to be cute and funny. Not something to fight about. ::Rolls Eyes::

  102. bb says:

    erm….this is great but how do I write it for someone else to figure out…how much do I write, no idea about the math, help please thank you

  103. Gusano says:

    The formula is WRONG. I know you swap the sign when you divide by a negative, but the numerators were negative too, so you would have -i if you want to get rid of the – signs. Or, you could just do -7/-7 =1 and -21/-7=3 and leave the > as it is cuz your values are positive and there is no reason to swap it.

    To prove it is wrong just give it values… let’s say i=4 and u=1
    if you do -7(4)/-7 > -21(u)/-7 everything is fine cuz if you solve it it gives you 4>3, but if you replace them on the last formula you get (4)<3(1) which is wrong cuz if you solve it it gives you 4 < 3 and as far I know 4 is greater than 3, so that proves the formula is absolutely wrong.

    The important thing is not to remember the theory you heard at school but knowing how to apply it correctly.

  104. Piano_Prodigy_U_FAIL says:

    WHAT IN THE WORLD? Guys, who cares, the whole point is that you are a nerd and love that person. BESIDES, you guys are so unimaginative. And, anyone who hates on me, well, you fail. Because, remember, fighting on the internet is like being Edward Cullen. No matter how right you are, you’re still a sparkling, pedophile fairy. :)

  105. Djdkks says:

    9x+7i < 3(3x+7u)

  106. graham says:

    this is not really correct becuase you cannot meaningfully talk about inequalities of imaginary numbers. is i > or < 1, for example?

  107. jim says:

    Technically he’s saying I greater than 3 of u lol

  108. me says:

    all this disscusion changed i<3u to i</3u hahahaha

  109. skyblue says:

    wow…that’s so cute..

  110. Bianca says:

    You idiots!! The equation is correct! You freakin’ flip the “>” to a “<" when dividing the -7! OMG!! IT DOESN'T TAKE HARD THINKING TO GET THIS RIGHT PEOPLE!!

    AND the "i" is not used as a freakin' imaginary number!! It's used as a variable!! like an "x"!

  111. i'm says:

    -7i > -21u
    i -21
    2 < 3

    it's right!

  112. bob says:

    “i” is equal to the sqrt(-1)

  113. AwesomeGuy307 says:

    Technically, “i” doesn’t exist as a number, since it represents the square root of -1.

  114. Jacob says:

    Man, people are idiots, i learned how to do this and harder problems in 6th grade.

  115. Derpy Hoves says:

    CORRECTED VERSION

    -9x – 7i > -3(3x + 7u)
    ————————–
    -9x – 7i > -9x – 21u
    +9x +9x
    ————————–
    -7 > -21u
    — —-
    -7 -7
    ————————–

    i <3 u

  116. Nathan says:

    to all the people arguing over the math:
    JUST GET A F**KING GRAPHING CALCULATOR
    -genius

  117. mathgeek says:

    most trying to correct this are wrong for different reasons. the sign flips because it is to find “i” not “-i” …to get the desired outcome, we have to turn the signs. it is all mathematically correct, and anyone who says otherwise should go learn basic algebra

  118. Richard Hwang says:

    if you divide by -9x,suppose you divide each term in the equation. which i didn’t see that. therefore mathematically your way of saying i love you in math is wrong.

  119. Richard Hwang:hwangster5k@hotmail.com says:

    you guys wasting time just enter the equation in WolframAlpha and see the real deal and stop arguing…

  120. Arc says:

    Minecraft Got Me Here

  121. Elyssa says:

    I’m laughing reading the comments! I’m a freshman, and I could’ve solved this when I was 11. And I’m writing the initial equation 9x-7i < 3(3x-7u). On my friend's valentine card. He loves solving math problems, and it'll be cute when he gets to the simplified equation.

  122. Jose says:

    i’m 14 and am passing algebra with flying colors, so lets get to the argued point, yes the inequality is correct. why? because when dividing by a negative the inequality sign changes. if it was less than() and vice versa.


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